1. (a) 4th order overall
         rate =  k[A]⁴
                    k[A]³[B]
                    k[A]²[B]²
                    k[A][B]³
                    k[B]⁴
     (b)  rate = k[A][B]³       (c) k = 2.56 M^-3s^-1      (d) rate = k[A][B]³ =(2.56M^-3s^-1)(1M)(2m)³ = 20.5M/S

2. (a) 3rd order overall
          rate = k[A]³                                   rate =  k[B]²[A]
                    k[B]²[C]                                  k[B]³
                    k[A]²[B]                                   k[C]³
                    k[A]²[C]                                   k[C]²[A]
                    k[A][B][C]                               k[C]²[B]

      (b)  rate = k[A]²[C]
            Runs 1 & 2 confirm 3rd order overall
            Runs 3 & 4 confirm zero order in B
            Runs 2 & 3 confirm 2nd order in A (when A increases 1.5X,rate increases 1.5²  or 2.25X)

     (c) k = 81.3 M^-2s^-1
     (d) rate = k[A]²[C] = (81.3M^-2s^-1)(0.5M)²(0.5M) = 10.2M/s

3.  (a)  rate = k[B]³
     (b) k = 1.00x10²M^-2s^-1
     (c) rate = k[B]³ = (1.00x10²M^-2s^-1)(1.0M)³ = 1.00x10²M/s

4.  Ea = R [(T₁T₂)(T₂-T₁)]ln(k₂/k₁) = (0.00831)[(400)(425)/(25)]ln3 = 62.1 kJ/mol

5.   ln(k₂/k₁) = [(Ea)/(R)][(T₂-T₁)/(T₁T₂)] = 2.79     k₂/k₁ = 16.3

6.   ln(k₂/k₁) = [(Ea)/(R)][(T₂-T₁)/(T₁T₂)]
            ln 10 = [(83.1)/0.00831)][(T₂-373)/(373T₂)]
            T₂ = 408K = 135°C